Which factorizations can be used to identify the real zeros of the function f(x) = -20x^2 + 23x - 6 ?

Answer:see explanationStep-by-step explanation:To find the zeros equate f(x) to zero, that is- 20x² + 23x - 6 = 0 ( multiply through by - 1 )20x² - 23x + 6 = 0To factorise the quadraticConsider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term, that isproduct = 20 × 6 = 120 and sum = - 23The factors are - 15 and - 8Use these factors to split the x- term20x² - 15x - 8x + 6 = 0 ( factor the first/second and third/fourth terms )5x(4x - 3) - 2(4x - 3) = 0 ← factor out (4x - 3)(4x - 3)(5x - 2) = 0Equate each factor to zero and solve for x4x - 3 = 0 ⇒ 4x = 3 ⇒ x = [tex]\frac{3}{4}[/tex]5x - 2 = 0 ⇒ 5x = 2 ⇒ x = [tex]\frac{2}{5}[/tex]