Answer:D.Step-by-step explanation:[tex]<,\ \leq-\text{shaded at the bottom of the line}\\>,\ \geq-\text{shaded at the top of the line}\\--------------------------------\\\text{Calculate the y-intercept. Put x = 0.}\\\\4x-2y\leq0\to4(0)-2y=0\\\\-2y=0\qquad\text{divide both sides by (-2)}\\\\y=0\\\\5x+3y\leq-11\to5(0)+3y=-11\\\\3y=-11\qquad\text{divide both sides by 3}\\\\y=-\dfrac{11}{3}\to y=-3\dfrac{2}{3}[/tex][tex]\text{Now specify on which side of the line we are shading.}\\\\4x-2y\leq0\qquad\text{add}\ 2y\ \text{to both isdes}\\\\4x\leq2y\qquad\text{divide both sides by 2}\\\\2x\leq y\to y\geq2x\to\text{shaded at the top of the line}\\------------------------\\5x+3y\leq-11\qquad\text{subtract 5x from both sides}\\\\3y\leq-5x-11\qquad\text{divide both sides by 3}\\\\y\leq-\dfrac{5}{3}x-\dfrac{11}{3}\to\text{shaded at the bottom of the line}[/tex]LOOK AT THE PICTURES